[SLUG] bash

[Minh Van <mle@nospam.mail.usyd.edu.au>]

given the expression:

1. if [ -n $dirname ] && [ \( -d $dirname \) -a \( -x $dirname \) ];
then

in bash, i don't understand why it is any different and less tedious from:

2. if [ -n $dirname ] && [ -d $dirname ] && [ -x $dirname ]; then

could somebody explain the reason or need to have embedded boolean
constructs and escaped parentheses in the first expression ?

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