[SLUG] Re: Perl Q

[Angus Lees <gusl@nospam.cse.unsw.edu.au>]

On Wed, Jul 12, 2000 at 01:46:05PM +1000, Rick Welykochy wrote:
> On Wed, 12 Jul 2000, Michael Lake wrote:
> > > Don't do that. In order to do what you want, you need to be using
> > > array references.
> > > return \(@nospam.a, @nospam.b);
> 
> The above will return a reference to the concatenated
> array @nospam.a, @nospam.b ... not what you want.


apparently not. from perlref(1p):

           Note that taking a reference to an enumerated list is
           not the same as using square brackets--instead it's
           the same as creating a list of references!

               @nospam.list = (\$a, \@nospam.b, \%c);
               @nospam.list = \($a, @nospam.b, %c);      # same thing!

(i thought the same as you too)

oh, and of course:

           As a special case, \(@nospam.foo) returns a list of
           references to the contents of @nospam.foo, not a reference to
           @nospam.foo itself.  Likewise for %foo, except that the key
           references are to copies (since the keys are just
           strings rather than full-fledged scalars).

isn't perl wonderful ;)

-- 
 - Gus


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